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I need to adjust a recipe for a stuffed chicken. The recipe calls for a 2kg chicken, and say W grams of stuffing. Now I plan on buying a smaller chicken because it's for less people, how can I estimate the amount of stuffing I'd need for the smaller chicken? Is the ratio the same as for the weight ration?

As an example, suppose I buy a 1kg chicken instead of a 2kg one. The ratio is now ½. For the small chicken, do I need ½ x W grams of stuffing, or more, or less?

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Are you cooking the stuffing separately, or are you actually stuffing it into the chicken? –  derobert Dec 10 '12 at 17:36
    
Stuffing it into the chicken, in this particular case. –  Jeroen Dec 10 '12 at 18:18

1 Answer 1

up vote 3 down vote accepted

I think you are over thinking this...

One one hand, the size of the cavity in the chicken is approximately proportional to the width or height of the chicken, and the width is approximately proportional to the cube root of the weight. However, for small values, the because of the cube law, the volume of the cavity is not going to change by huge amounts--a 2.5 kg chicken will take almost as much stuffing as a 3 kg chicken.

From 2 to 3 kg, you are looking at a ratio of approximately 1.4 versus 1.7, or very approximately 80 percent as much stuffing. For most cooks, this is in the noise, I would suspect.

However, speaking culinary:

  1. You can simply look at your chicken and estimate the volume of the cavity, or stuff it until it is full--see item 2.
  2. You can bake any excess stuffing separately in a casserole dish. Or you can bake all of the stuffing (technically, now dressing) in a casserole, which is my preferred method--then the amount you want is directly proportional to the number of guests you have.*
  3. Many folks, including myself, believe roasting the chicken (or turkey) without stuffing leads to better meat, is easier, and the chicken will certainly cook more quickly.
  4. Lots of folks like the stuffing the best, so your guests might want lots.
  5. Leftover stuffing is delicious, and can be frozen.

*Geeks may point out that the guests may have to be weighted by a hunger factor...

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This is all balderdash. To see why, assume a spherical chicken... –  Josh Caswell Dec 10 '12 at 18:18
    
Yes, darn it, I assumed a spherical chicken to get orders of magnititude. Even with a 20% error factor, I think it is definitely in the ball park for the reasoning :-) It would work the same with a cubic chicken :-) –  SAJ14SAJ Dec 10 '12 at 18:20
    
The chicken's cavity should actually be considered to be a tesseract which can be filled with more stuffing than its 3-dimensional volume. That's the only way to get the ratio right. –  Josh Caswell Dec 10 '12 at 18:29
3  
All animals are spheres of uniform density—sometimes even points—we all learned this in physics, it makes the math so much easier! While we're at it, collisions with them are fully elastic. This is important, it makes it easier to pick up your chicken when you drop it, it just bounces back into your hands. Imagine how much work that would have saved Julia Child (hey, it has as much truthiness as the uniform chicken) –  derobert Dec 10 '12 at 18:30
    
@JoshCaswell I was thinking of the one that goes: in theory, all horses are spherical :-) I just want to know where to get the 4-dimensional stuffing to fill the tesseract. –  SAJ14SAJ Dec 10 '12 at 18:31

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