I have 0.3 kg of corn syrup at room temperature (294 K). The specific heat of corn syrup is [2.72 kJ/(kg K)]. I want to heat it up in a 1,000 W microwave until it reaches 394 K.
I know that
q = 0.3 kg * 2.72 kJ/(kg K) * 100 K
q = 81.6 kJ = 82 seconds in a 1,000 W (1 kJ/second) microwave.
From my experience, it takes longer than 82 seconds to heat up corn syrup that much.
How should I account for extraneous variables?
From Chris H's Answer: 82 seconds to raise the temperature + 111 seconds to boil off the water = 3 minutes, 13 seconds in a 1,000 Watt microwave.